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November 27, 2014

November 27, 2014

Posted by **ANON** on Sunday, September 30, 2012 at 2:09pm.

thus f-1(x)=2-sqrt(-x+6)

i need to show that f(f-1(x))=x, but i keep getting negative x...any help

- precalc -
**Reiny**, Sunday, September 30, 2012 at 3:28pmby definition ...

f(f^-1 (x)) = x , but anyway ...

f( f^-1(x) )

= f(2 - √(6-x) )

= 2 + 4(2 - √(6-x) ) - (2 - √(6-x) )^2

= 2 + 8 - 4√(6-x) - (4 - 4√(+-x) + 6-x)

= 10 - 4√(6-x) - 4 + 4√(6-x) - 6 + x

= x

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