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March 28, 2017

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A man on a 2m high ladder throws a ball in the air with an initial velocity of 22m/s. If the ball is not caught by the man and instead hits the ground, how long was it in the air and how high did it go?

  • Physics - ,

    Tr = (V-Vo)/g = (0-22)/-9.8 = 2.24 s. =
    Rise time.
    hmax = ho + Vo*t + 0.5g*t^2.
    hmax = 2 + 22*2.24 - 4.9*(2.24)^2 = 26.7m. Above gnd.

    hmax = Vo*t + 0.5g*t^2 = 26.26.7m.
    0 + 4.9t^2 = 26.7
    4.9t^2 - 26.7 = 0.
    Use Quadratic Formula:
    Tf = 2.33 s. = Fall time.

    Tr + Tf = 2.24 + 2.33 = 4.57 s. = Time
    in air.

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