Posted by **Anonymous** on Sunday, September 30, 2012 at 8:48am.

A projectile motion thrown with velocity of 200m/s direction of 53 degree above the horizontal?determine height,range,total time,time at particle reach maximum height?

- Physics -
**Damon**, Sunday, September 30, 2012 at 10:18am
solve two problems separately

Problem 1 - vertical

Vi = 200 sin 53

v = Vi - 9.8 t

top when

0 = Vi -9.8 t solve for t

That t is half the time it is in the air

h = Vi t - 4.9 t^2 at time t

total time in air = 2 t

Problem 2, horizontal

u = Vi cos 53 until it crashes

d = u * total time = 2 u t

- Physics -
**Robert**, Monday, April 25, 2016 at 11:10pm
Max Height = 1,306M

Range = 3,840M

Hangtime/Total Time = 32 seconds

Time to reach max height = 16 seconds

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