The ratio of the number of coins Azam had to the number of coins Eddie had was 3:7. Eddie gave 42 coins to Azam and they ended up having the same number of coins. How many coins did each person have at first?

To solve this problem, we can follow these steps:

Step 1: Set up a system of equations based on the given information.
Let's assume that Azam initially had 3x coins and Eddie initially had 7x coins.

Step 2: Express the change in coins after Eddie gives some to Azam.
After Eddie gives 42 coins to Azam, Azam will have a total of 3x + 42 coins, and Eddie will have 7x - 42 coins.

Step 3: Set up an equation based on the fact that they ended up having the same number of coins.
Since they ended up with the same number of coins, we can write the equation:
3x + 42 = 7x - 42

Step 4: Solve the equation.
Subtract 3x from both sides of the equation:
42 = 4x - 42

Add 42 to both sides of the equation:
84 = 4x

Divide both sides of the equation by 4:
x = 21

Step 5: Find the initial number of coins for each person.
Substitute the value of x back into the expressions we assumed earlier:
Azam initially had 3x coins = 3 * 21 = 63 coins
Eddie initially had 7x coins = 7 * 21 = 147 coins

Therefore, Azam initially had 63 coins and Eddie initially had 147 coins.

This is the same style and method as the one I just did for you.

Try to follow the same procedure and then check your answer.

42 divided by 7 = 6

1 unit=6
6*42=