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pre-calculus

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solve the the following inequality. write your solution in interval notation.

x^3-49x<0
_ (I don't know how to make the sign on my computer)

  • pre-calculus - ,

    x^3 - 49x < 0
    x(x^2 - 49) < 0
    x(x+7)(x-7) < 0

    consider f(x) = x(x+7)(x-7)
    the x-intercepts would be -7, 0, 7

    Knowing the basic shape of a cubic, we have
    x < -7 OR 0 < x < 7

    I will let you write that in the interval notation that you learned.

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