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July 31, 2014

July 31, 2014

Posted by **ladybug** on Saturday, September 29, 2012 at 11:29pm.

x^3-49x<0

_ (I don't know how to make the sign on my computer)

- pre-calculus -
**Reiny**, Sunday, September 30, 2012 at 8:12amx^3 - 49x < 0

x(x^2 - 49) < 0

x(x+7)(x-7) < 0

consider f(x) = x(x+7)(x-7)

the x-intercepts would be -7, 0, 7

Knowing the basic shape of a cubic, we have

x < -7 OR 0 < x < 7

I will let you write that in the interval notation that you learned.

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