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2KClO3 (s) ---> 2KCl (s) + 3O2 (g)

For every mole of KClO3 that decomposes in the above experiment, how many grams of oxygen gas are produced?

A.) 3 B.) 16 C.) 48

  • Chem. - ,

    How many mols O2 are produced? That's 1 mol KClO3 x (3 mols O2/2 mol KClO3) = 3/2 mol.
    3/2 mol x molar mass = g = about 48 or so. right?

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