posted by Anonymous on .
2KClO3 (s) ---> 2KCl (s) + 3O2 (g)
For every mole of KClO3 that decomposes in the above experiment, how many grams of oxygen gas are produced?
A.) 3 B.) 16 C.) 48
How many mols O2 are produced? That's 1 mol KClO3 x (3 mols O2/2 mol KClO3) = 3/2 mol.
3/2 mol x molar mass = g = about 48 or so. right?