Posted by **Teisha** on Saturday, September 29, 2012 at 8:23pm.

Given triangle ABC, AD bisects angle BAC,and AE=ED

Prove AE/AC=BD/BC

Because I cant draw it I will explain. Its a triangle, A is the point at the top, B is the point at the bottom left and C is the point at the bottom right.There is a line going right down the middle, which is point D. So point D is between point B and C. From point D there is a short line which goes to the middle of points A and C, this point is E.

## Answer This Question

## Related Questions

- maths - in triangle abc angle b = 2angle c.d is a point ob bc such that ad ...
- Math(Geometry) - In the diagram below(no diagram but details will be provided), ...
- GEOMETRY - GIVEN: TRIANGLE ABC,AD bisects <BAC,and AE=ED, PROVE:AE/AC=BD/BC
- Geometry - Given: segment BD bisects angle ABC; AB=BC. Prove: triangle ABD ...
- geometry - TWO COLUMN TRIANGLE PROOF Given: line AB is parallel to line DE, and ...
- geometry - The medial triangle of a triangle ABC is the triangle whose vertices...
- Maths - X and Y are points on the sides BC and AC of a triangle ABC respectively...
- geometry proofs - given ABC is a triangle. Ad is the altitude to BC. Ad biscects...
- Math - In triangle ABC, D bisects side BC, G bisects side AB, and the points E ...
- Math - In triangle ABC, D bisects side BC, G bisects side AB, and the points E ...

More Related Questions