posted by Alexis .
A hydraulic lift office chair has its seat attached to a piston with an area of
. The chair is raised by exerting force on another piston, with an area
of 4.12 cm2
. If a person sitting on the chair exerts a downward force of 219 N,
what force needs to be exerted on the small piston to lift the seat?
Force on big piston/force on small piston = 11.2/4.12 = 2.72 which is the mechanical advantage of our hydraulic jack machine
219/2.72 = 80.5 Newtons
That is a pretty light person by the way.
11.2/4.12=2.72, 219/2.72=80.5 N
thanks Ms. Smith!