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December 19, 2014

December 19, 2014

Posted by **Hanu** on Saturday, September 29, 2012 at 3:45pm.

b) What is the coefficient of kinetic friction between a rubber tire and the road if a 2000 kg car needs 1.57 × 104 N to keep the car moving at a constant speed?

- Physics -
**Damon**, Saturday, September 29, 2012 at 5:45pmnormal force = m g = 10*9.81

so

friction force max = .3 * 10 * 9.81

which is min horizontal force required to start acceleration

F = m a

a = 0

so

friction Force - pulling force = 0

mu * 2000 * 9.81 = 1.57 * 10^4

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