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March 30, 2017

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A bicyclist makes a trip that consists of three parts, each in the same direction (due north) along a straight road. During the first part, she rides for 22 minutes at an average speed of 6.50m/s. During the second part, she rides for 36 minutes at an average speed of 4.30m/s. Finally, during the third part, she rides for 8.0 minutes at an average speed of 13.7m/s. How far has the bicyclist traveled during the entire trip?

b). What is her average velocity for the trip?

  • Physics - ,

    Convert min. to seconds:
    t1 = 22min * 60s/min = 1320 s.
    t2 = 36min * 60s./min = 2160 s.
    t3 = 8min * 60s/min = 480 s.

    a. D = V1*t1 + V2*t2 + V3*t3.
    D = 6.5*1320 + 4.30 * 2160 + 13.7*480 =
    24,444 m. = Total dist. traveled.

    b. T = t1 + t2 + t3.
    T=1320 + 2160 + 480=3960 s.=Tot. time.
    Vavg = D/T = 24444m/3960s = 6.17 m/s.

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