Friday

January 30, 2015

January 30, 2015

Posted by **Nixie** on Friday, September 28, 2012 at 8:44pm.

- Algebra -
**Reiny**, Saturday, September 29, 2012 at 12:09amlet one be $x

the other $ (2000-x)

.09x + .06(2000-x) = 129

times 100

9x + 6(2000-x) = 12900

9x + 12000 - 6x = 12900

3x = 900

x=300

$300 was invested at 9%, and 1700 was invested at 6%

check:

.09(300) + .06(1700) = 129

**Answer this Question**

**Related Questions**

algebra - An investor invested a total of $2200 in two mutual funds. One earned ...

Algebra - An investor invested a total of 1,400 in two mutual funds. One fund ...

Algebra - An investor invested a total of $1400 in two mutual funds. One fund ...

algebra - an investor invested a total of 1,100 in two mutual funds. One fund ...

algebra - An investor invested a total of $2,600 in two mutual funds. One fund ...

algebra - An investor invested a total of $500 in two mutual funds. One fund ...

Mat/116 - An investor invested $3,400 in two mutual funds.One fund earned a 6%...

MAT116 - An investor invested a total of $3,400 in two mutual funds. One fund ...

math - an investor invested a total of $2,900 in two mutual funds. One fund ...

mat/116 - Please help me slove this question. An investor invested a total of $3...