calculate the average volume of sodium hydroxide required for the titration of 25.00mL of the standard sulfuric acid solution.
From my data i have trial 1 and 2 to be 19.80ml and 19.80ml of NaOH used so do i just add them and divide it by two to get the average?
Yes, but if both volumes are 19.80 mL you know the average will be 19.80.
How do I type I2 meaning Iodine
I2 is elemental iodine.
If you REALLY want to go the to trouble you can write it as I2 but that takes too much time and everyone who uses this forum understands that I2 means I with a subscript 2.
To calculate the average volume of sodium hydroxide (NaOH) required for the titration of sulfuric acid, you will indeed need to calculate the mean of the two given values. Here are the steps to determine the average volume:
1. Add the two trial values together: 19.80 mL + 19.80 mL = 39.60 mL.
2. Divide the sum by the number of trials (in this case, 2): 39.60 mL ÷ 2 = 19.80 mL.
Therefore, the average volume of NaOH required for the titration is 19.80 mL.