A car of mass m = 1635 kg is pushed off a cliff of height h = 23 m. If the car lands a distance of 9 m from the base of the cliff, what was the kinetic energy of the car the instant after it left the cliff?
how long is it in the air?
h= 1/2 g t^2
time in air=sqrt(2h/g)=sqrt(46/9.8) you figure that.
now 9m=vhoriz*time in air. Figure Velocity horizontal v
then KE=1/2 m v^2