math
posted by Melissa on .
Each dividend was divided by another polynomial, resulting in the given quotient and remainder. Find the divisor
Divided:5x^3+x^2+3 ,quotient:5x^214x+42, remainder:123

we know that
5x^3+x^2+3 = p(x)*(5x^214x+42)  123
so,
5x^3 + x^2 + 126 = p(x)*(5x^2  14x + 42)
a simple long division yields p(x) = (x+3)