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March 27, 2017

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A bicycle wheel of radius 0.4 m is spinning at a rate of 40 revolutions per minute.

What is the centripetal acceleration of a point on the edge of the wheel?

What is the period of the wheel's motion?

  • physics - ,

    40rpm=80PI/60 radians/s =1 1/3 PI rad/s=w

    centripetal acceleartion=w^2 r

    Period=1/freq=2PI/w

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