Post a New Question


posted by .

A bicycle wheel of radius 0.4 m is spinning at a rate of 40 revolutions per minute.

What is the centripetal acceleration of a point on the edge of the wheel?

What is the period of the wheel's motion?

  • physics -

    40rpm=80PI/60 radians/s =1 1/3 PI rad/s=w

    centripetal acceleartion=w^2 r


Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question