physics
posted by phil on .
A bicycle wheel of radius 0.4 m is spinning at a rate of 40 revolutions per minute.
What is the centripetal acceleration of a point on the edge of the wheel?
What is the period of the wheel's motion?

40rpm=80PI/60 radians/s =1 1/3 PI rad/s=w
centripetal acceleartion=w^2 r
Period=1/freq=2PI/w