Saturday

September 20, 2014

September 20, 2014

Posted by **Nami** on Friday, September 28, 2012 at 10:52am.

What is the height of the cliff?

What is the maximum height of the ball?

What is the ball's impact speed?

Please provide the Formulas and steps!

Thank You!

- Physics -
**Henry**, Saturday, September 29, 2012 at 9:11pmVo = 27m/s @ 60o

Xo = 27*cos60 = 13.5 m/s.

Yo = 27*sin60 = 23.4 m/s.

Tr = (Y-Yo)/g = (0-23.4)/-9.8 = 2.39 s.=

Rise time.

hmax = Yo*t + 0.5g*t^2.

hmax = 23.4*2.39 - 4.9*(2.39)^2=27.84 m.

Tr + Tf = 3.0 s.

2.39 + Tf = 3

Tf = 3 - 2.39 = 0.61 s. = Fall time.

h = hmax - 0.5g*Tf^2.

h = 27.84 - 4.9*(0.61)^2 = 23.3 = Ht. of cliff.

V = Vo + gt = 0 + 9.8*0.61 = 5.98 m/s.=

Impact velocity of ball.

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