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March 25, 2017

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The Ka of a monoprotic weak acid is 3.29 × 10-3. What is the percent ionization of a 0.176 M solution of this acid?

  • Chemistry - ,

    ............HA --> H^+ + A^-
    I........0.176.....0......0
    C.........-x.......x.......x
    E.......0.176-x....x.......x

    Ka = (H^+)(A^-)/(HA)
    Substitute from the ICE chart into the Ka expression and solve for H^+.
    %ionization = [(H^+)/0.176]*100 = ?

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