Posted by Becky on Thursday, September 27, 2012 at 8:48pm.
if u and v are functions of x,y,z, then the normals are
Nu = ∇u
Nv = ∇v
The tangent line of the intersection is perpendicular to both normals
T(x,y,z) = ∇u × ∇v
∇u = 2xi + 2yj - k
∇v = 12xi + 10yj + 14zk
T(-1,1,2) = 33i + 34j + 2k
so that would be
x = -1 + 33t
y = 1 + 34t
z = 2 + 2t
can you please explain to me where you got the numbers for T(-1,1,2) I know you did the cross product but I can not seem to get the same numbers as you. Please explain
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