physic
posted by mike on .
A ball rolls off the edge of a balcony at 10 m/s. what is the speed after 1s in the air?

vertical: vf=gt=9.8m/s
horizontal: v=10
speed=sqrt(Vf^2+v^2)
posted by mike on .
A ball rolls off the edge of a balcony at 10 m/s. what is the speed after 1s in the air?
vertical: vf=gt=9.8m/s
horizontal: v=10
speed=sqrt(Vf^2+v^2)