Posted by Diego on Thursday, September 27, 2012 at 8:43pm.
A tennis ball with a velocity of 24.4 m/s
is thrown perpendicularly at a wall. After
striking the wall, the ball rebounds in the
opposite direction with a speed of 16 m/s.
If the ball is in contact with the wall for
0.013 s, what is the average acceleration of
the ball while it is in contact with the wall?
Answer in units of m/s
2

Physics  bobpursley, Thursday, September 27, 2012 at 8:52pm
acceleration=changevelocty/time=(24.4+16)/.013 m/s^2

Physics  Diego, Thursday, September 27, 2012 at 9:03pm
24.4+16? If it's the change of velocity, wouldn't it be 24.416?

Physics  Latoyia, Friday, October 21, 2016 at 7:46am
a=1624.4/.013
a=40.4/.013
a=3107.69
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