Posted by **Diego** on Thursday, September 27, 2012 at 8:43pm.

A tennis ball with a velocity of 24.4 m/s

is thrown perpendicularly at a wall. After

striking the wall, the ball rebounds in the

opposite direction with a speed of 16 m/s.

If the ball is in contact with the wall for

0.013 s, what is the average acceleration of

the ball while it is in contact with the wall?

Answer in units of m/s

2

- Physics -
**bobpursley**, Thursday, September 27, 2012 at 8:52pm
acceleration=changevelocty/time=(24.4+16)/.013 m/s^2

- Physics -
**Diego**, Thursday, September 27, 2012 at 9:03pm
24.4+16? If it's the change of velocity, wouldn't it be 24.4-16?

- Physics -
**Latoyia**, Friday, October 21, 2016 at 7:46am
a=-16-24.4/.013

a=-40.4/.013

a=3107.69

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