Posted by **Avi** on Thursday, September 27, 2012 at 7:00pm.

Two commercial airplanes are flying at an altitude of 40,000 ft along straight-line courses that intersect at right angles. Plane A is approaching the intersection point at a speed of 429 knots (nautical miles per hour; a nautical mile is 2000 yd or 6000 ft.) Plane B is approaching the intersection at 460 knots.

At what rate is the distance between the planes decreasing when Plane A is 2 nautical miles from the intersection point and Plane B is 6 nautical miles from the intersection point?

Answer = knots.

## Answer This Question

## Related Questions

- Calc - Two commercial airplanes are flying at an altitude of 40,000 ft along ...
- Calc - Two commercial airplanes are flying at an altitude of 40,000 ft along ...
- Calculus - At noon, ship A is 50 nautical miles due west of ship B. Ship A is ...
- calculus - At noon, ship A is 10 nautical miles due west of ship B. Ship A is ...
- calculus - At noon, ship A is 10 nautical miles due west of ship B. Ship A is ...
- calculus - At noon, ship A is 10 nautical miles due west of ship B. Ship A is ...
- calculus - At noon, ship A is 30 nautical miles due west of ship B. Ship A is ...
- CALCULUS - At noon, ship A is 40 nautical miles due west of ship B. Ship A is ...
- Calculus - At noon, ship A is 20 nautical miles due west of ship B. Ship A is ...
- Calculus - At noon, ship A is 10 nautical miles due west of ship B. Ship A is ...

More Related Questions