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March 31, 2015

March 31, 2015

Posted by **Brianna** on Thursday, September 27, 2012 at 2:39pm.

- Physics based Calculus -
**Steve**, Thursday, September 27, 2012 at 4:48pmheight of ball above cliff is

h = 5 + vy*t - 16t^2

assuming vy is y-component of maximum speed of 86 mph = 126.13 ft/s

h = 0 after .910 sec, so

vy = 9.1 ft/s

now, vy^2 + vx^2 = v^2

9.1^2 + vx^2 = 126.13^2

vx = 125.8 ft/s

ball fell from cliff height

453/125.8 = 3.6 sec

after falling back to cliff height, the distance fallen to ground was

9.1t + 16t^2 = 241 ft

so, the cliff is 241 ft high

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