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March 30, 2015

March 30, 2015

Posted by **Kieran** on Thursday, September 27, 2012 at 9:24am.

So far i have

V=(1-2x)(2-2x)x

- Calc -
**Steve**, Thursday, September 27, 2012 at 11:32amso, figure dV/dx

dV/dx = 2(6x^2-6x+1)

dV/dx = 0 when x = 1/6 (3√3) = .211 or .789

Now .789 is impossible, since the width is only 1.

so, the cuts are .211m

- Calc -
**Kieran**, Thursday, September 27, 2012 at 12:30pmhow did you go from 0= 1/6 (3+-3)

- Calc -
**Steve**, Thursday, September 27, 2012 at 1:53pmdV/dx = 2(6x^2-6x+1

so, dV/dx = 0 when 6x^2-6x+1

solve the quadratic to get X = 1/6 (3√3)

this is calculus; algebra I should be no problem...

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