Posted by Amber on .
find a polynomial of least degree(having real coefficients) with zeros: 5, 2, 2i

Math 
bobpursley,
multiply this out:
(x5) (x^2+4)
I suspect you copied the problem wrong, it should be zeroes at 5, 2i, 2i 
Math 
Steve,
Unless there is the implicit assumption that if 2i is a root, so is 2i, so the polynomial would be
(x5)(x+2)(x^2+4) = x^4  3x^3  6x^2  12x  40