Posted by Amber on Thursday, September 27, 2012 at 3:45am.
find a polynomial of least degree(having real coefficients) with zeros: 5, 2, 2i

Math  bobpursley, Thursday, September 27, 2012 at 4:09am
multiply this out:
(x5) (x^2+4)
I suspect you copied the problem wrong, it should be zeroes at 5, 2i, 2i

Math  Steve, Thursday, September 27, 2012 at 11:21am
Unless there is the implicit assumption that if 2i is a root, so is 2i, so the polynomial would be
(x5)(x+2)(x^2+4) = x^4  3x^3  6x^2  12x  40
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