Posted by bballer on Thursday, September 27, 2012 at 12:44am.
Find the number of distinguishable permutations of the given letters ``AAABBBCCC''.
If a permutation is chosen at random, what is the probability that it begins with at least 2 A's?

math  dylan, Thursday, October 25, 2012 at 4:13am
9!/(1!*3!*3!)
you take the total amount of letters you have factorial, divided by each of you different types of letters factorial. the reason that there is a 1! in the beginning is because you have the first two A's in the front, so they won't be going anywhere, leaving you with 1 A, therefore, 1!.

math  q, Monday, December 7, 2015 at 6:53pm
123145
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