Posted by Jamie on Wednesday, September 26, 2012 at 10:02pm.
Find the maximum value of: y=3x^2 15x +1

College algebra  Steve, Thursday, September 27, 2012 at 10:54am
in any parabola ax^2+bx+c=0, the max value is attained at x = /2a.
So, here that would be when x = 15/6 = 5/2
y(5/2) = 19.75

College algebra  Aljebeth D. Tura, Friday, September 28, 2012 at 2:29am
another way of solcinf the problem is by deriving and setting dy/dx=0...but the above sol. is easier that but its disadv. is you may forget the formula.. :D
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