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April 19, 2014

April 19, 2014

Posted by **kieran** on Wednesday, September 26, 2012 at 9:54pm.

Dont really know Where to start with this one.

- Calculus -
**Steve**, Thursday, September 27, 2012 at 10:51amif the area enclosed is x by y, and the neighbor will pay for half the cost of the y side,

A = xy

C = 2x + 3/2 y

C = 2x + 3/2 (A/x)

dC/dx = 2 - 3A/(2x^2)

dC/dx = 0 when 3A/(2x^2) = 2

x = √(3A)/2

so, the lot is √(3A)/2 by 2√(A/3)

cost is thus √(3A) + 3/2 * 2√(A/3) = 2√(3A)

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