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July 31, 2014

July 31, 2014

Posted by **Kayla** on Wednesday, September 26, 2012 at 5:43pm.

Limit as x approaches pi/4 of (1-tanx)/(sinx-cosx)

I need step by step help using the special trignometric limits theorem.

- Calculus -
**Steve**, Wednesday, September 26, 2012 at 5:54pm(1-tanx)/(sinx-cosx) = 0/0, so try LHospital's Rule:

-sec^2(x)/(cosx+sinx) = (-2)/(2/√2) = -2/√2 = -√2

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