Posted by nithiya nithyananthan on Wednesday, September 26, 2012 at 11:18am.
it is required to make an open box of gregreatest possible volume from a square piece of tin,whose side is one metre' by cutting equal squares out of the corners and then folding up the tin to form the sides, what should be the length of a side of the sgures cut out/

math  Steve, Wednesday, September 26, 2012 at 11:49am
v = x(12x)^2
dv/dx = (x1)(3x1)
dv/dx = 0 when x=1 or 1/3
max v at x = 1/3
v(1/3) = 1/3 (2/3)^2 = 4/27