Monday
March 27, 2017

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Technetium-99m is an ideal radioisotope for scanning organs because it has a half-life of 6.0 {\rm hr} and is a pure gamma emitter. Suppose that 280{\rm mg} were prepared in the technetium generator this morning. How many milligrams would remain after the following intervals?

• chemistry - ,

Technetium-99m is an ideal radioisotope for scanning organs because it has a half-life of 6.0 {\rm hr} and is a pure gamma emitter. Suppose that 280{\rm mg} were prepared in the technetium generator this morning. How many milligrams would remain after the following intervals?

• chemistry - ,

no intervals but here is how you do it.
k = 0.693/t1/2

ln(No/N) = kt
No = 280 mg
N = unknown
k from above
t = intervals in the problem (in hours).