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chemistry

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Technetium-99m is an ideal radioisotope for scanning organs because it has a half-life of 6.0 {\rm hr} and is a pure gamma emitter. Suppose that 280{\rm mg} were prepared in the technetium generator this morning. How many milligrams would remain after the following intervals?

  • chemistry - ,

    Technetium-99m is an ideal radioisotope for scanning organs because it has a half-life of 6.0 {\rm hr} and is a pure gamma emitter. Suppose that 280{\rm mg} were prepared in the technetium generator this morning. How many milligrams would remain after the following intervals?

  • chemistry - ,

    no intervals but here is how you do it.
    k = 0.693/t1/2

    ln(No/N) = kt
    No = 280 mg
    N = unknown
    k from above
    t = intervals in the problem (in hours).

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