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October 30, 2014

October 30, 2014

Posted by **Anonymous** on Wednesday, September 26, 2012 at 1:39am.

Function: 1/square root of x

Line: x+2y-6=0

- Calculus-math -
**Scott**, Wednesday, September 26, 2012 at 2:20pmusing slope-intercept, the given slope is -1/2

the slope of the tangent to the function is the 1st derivative

f(x) = 1 / sqrt(x) = x^(-1/2)

f'(x) = (-1/2) x^(-3/2)

substitute to find x and then y at the point of tangency

use point-slope to write the equation of the new parallel line

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