Posted by **Anonymous** on Wednesday, September 26, 2012 at 1:35am.

Find an equation of the line that is tangent to the graph f and parallel to the given line

Function: f(x)= 1/ square root of x

Line: x+2y-6=0

- calculus -
**Steve**, Wednesday, September 26, 2012 at 11:02am
slope of f(x) is -1/(2x√x)

slope of line: -1/2

so, you want -1/(2x√x) = -1/2

x=1

so, you now have a slope=1 and a point (1,1).

(y-1) = (-1/2)(x-1)

y = -x/2 + 3/2

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