Posted by **Anonymous** on Wednesday, September 26, 2012 at 1:35am.

Find an equation of the line that is tangent to the graph f and parallel to the given line

Function: f(x)= 1/ square root of x

Line: x+2y-6=0

- calculus -
**Steve**, Wednesday, September 26, 2012 at 11:02am
slope of f(x) is -1/(2x√x)

slope of line: -1/2

so, you want -1/(2x√x) = -1/2

x=1

so, you now have a slope=1 and a point (1,1).

(y-1) = (-1/2)(x-1)

y = -x/2 + 3/2

## Answer this Question

## Related Questions

- Calculus-math - Find an equation of the line that is tangent tothe graph of f ...
- calculus - 5. Let f be the function given by f(x) = x3- 7x + 6. a. Find the ...
- Calculus - Given the function defined as f(x)=x^3-(3/2)x^2-6x+10 a) Explain why ...
- Calculus - Given the function defined as f(x)=x^3-(3/2)x^2-6x+10 a) Explain why ...
- Math- Calculus - Find an equation of the line that is tangent to the graph of f ...
- MATH - Find an equation of the line that is tangent to the graph of f and ...
- Calculus - Find an equation of the line that is tangent to the graph of f and ...
- HS Calculus - Definition of the derivative to calculate f'(x) if f(x) = square ...
- Calculus - Given the function y=(x^2-5/x+3), answer the following questions. a) ...
- Math please help - Find an equation of the line that is tangent to the graph of ...

More Related Questions