Post a New Question

math

posted by on .

Suppose that a department contains 11 men and 19 women. How many ways are there to form a committee with 6 members if it must have strictly more women than men?

  • math - ,

    cases:
    6W0M
    5W1M
    4W2M
    3W3M -- no good

    number of cases
    = C(19,6) x C(11,0) + C(19,5) x C(11,1) + C(19,4) x C(11,2)
    = 27132 + 127908 + 213180
    = 368220

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question