Posted by **bballer** on Wednesday, September 26, 2012 at 12:30am.

Suppose that a department contains 11 men and 19 women. How many ways are there to form a committee with 6 members if it must have strictly more women than men?

- math -
**Reiny**, Wednesday, September 26, 2012 at 12:44am
cases:

6W0M

5W1M

4W2M

3W3M -- no good

number of cases

= C(19,6) x C(11,0) + C(19,5) x C(11,1) + C(19,4) x C(11,2)

= 27132 + 127908 + 213180

= 368220

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