Thursday

November 27, 2014

November 27, 2014

Posted by **Angie** on Tuesday, September 25, 2012 at 4:24pm.

My kelvin temperatures are:

298

308

318

328

338

348

358

368

378

Taking the natural log of both sides of both sides of the equation gives ln(k) = ln(A) – E/RT. Thus, a graph of the natural log of the reaction rate constant versus the inverse of the absolute temperature should be linear. Create such a graph to verify this is true.

- Chemistry -
**DrBob222**, Tuesday, September 25, 2012 at 4:27pm298 = T

inverse is 1/T = 1/298

**Answer this Question**

**Related Questions**

Chemistry - How can you calculate activation energy in (kj/mol)? When all that ...

Chem - Variation of the rate constant with temperature for the first-order ...

science, absolute zero - what is absolute zero? if 0 kelvin is the lowest ...

Pre calculus - Okay, I'm really fuzzy about my log and exponential chapter. For...

Chemistry - I had to find the absolute zero from a graph with the following ...

statistics - Finish times (to the nearest hour) for 59 dogsled teams are shown ...

chemistry - The rate constant,K, for a given was determined at a number of ...

Chemistry - 1. A gas initially at 10 C must be changed to _____ C to triple the ...

Chemistry - The multiple Choice Question: Determine delta G (free energy at ...

FSE 120 - A compartment measures 3.5 meters by 5.5 meters and is 3 meters high. ...