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n the theory of relativity, the mass of a particle with speed v is m=f(v)=m01−v2/c2√, where m0 is the rest mass of the particle and c is the speed of light in a vacuum. Letting m0=1, find f−1(10).

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    I believe the formula is

    f(v) = m0 / √(1-v^2/c^2)

    so, plugging your numbers, if I read it right, you want f -1(10), meaning you want to know how fast to go to make the mass increase by a factor of 10.

    10 = 1/√(1 - v^2/c^2)
    100 = 1/(1 - v^2/c^2)
    1 - v^2/c^2 = 1/100
    c^2 - v^2 = c^2/100
    v^2 = 99c^2/100
    v = √99/10 c = .995c

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