Tuesday

July 29, 2014

July 29, 2014

Posted by **Gus** on Tuesday, September 25, 2012 at 3:01pm.

- Math -
**Steve**, Tuesday, September 25, 2012 at 3:18pmI believe the formula is

f(v) = m_{0}/ √(1-v^2/c^2)

so, plugging your numbers, if I read it right, you want f^{ -1}(10), meaning you want to know how fast to go to make the mass increase by a factor of 10.

10 = 1/√(1 - v^2/c^2)

100 = 1/(1 - v^2/c^2)

1 - v^2/c^2 = 1/100

c^2 - v^2 = c^2/100

v^2 = 99c^2/100

v = √99/10 c = .995c

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