Posted by **Lauren** on Tuesday, September 25, 2012 at 1:48pm.

An elevator (cabin mass 600 kg) is designed for a maximum load of 2100 kg, and to reach a velocity of 3.1 m/s in 3 s. For this scenario, what is the tension the elevator rope has to withstand?

This is what I've tried and is incorrect.

2100kg + 600 kg= 2700kg (m)

(3.1/3)= 1.033m/s^2 (a)

2700 x 1.033= 2789.1N (F)

Please help.

## Answer this Question

## Related Questions

- Physics - An elevator (cabin mass 600 kg) is designed for a maximum load of 2800...
- Physics - An elevator (cabin mass 600 kg) is designed for a maximum load of 2800...
- physics - An elevator (cabin mass 540 kg) is designed for a maximum load of 3500...
- physics - Your engineering firm is asked to specify the maximum load for the ...
- Physics - A loaded elevator with very worn cables has a total mass of 3000 kg, ...
- Physics - An elevator in a tall building is allowed to reach a maximum speed of ...
- Physics - An elevator in a tall building is allowed to reach a maximum speed of ...
- physics - An elevator in a tall building is allowed to reach a maximum speed of ...
- physics - An elevator in a tall building is allowed to reach a maximum speed of ...
- Physics - While an elevator of mass 2681 kg moves upward, the tension in the ...