Friday
March 24, 2017

Post a New Question

Posted by on .

An elevator (cabin mass 600 kg) is designed for a maximum load of 2100 kg, and to reach a velocity of 3.1 m/s in 3 s. For this scenario, what is the tension the elevator rope has to withstand?

This is what I've tried and is incorrect.
2100kg + 600 kg= 2700kg (m)
(3.1/3)= 1.033m/s^2 (a)
2700 x 1.033= 2789.1N (F)
Please help.

  • Physics - ,

    you seem to have forgotten gravity

    add g to your acceleration number and you should be okay

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question