Posted by **Lauren** on Tuesday, September 25, 2012 at 1:48pm.

An elevator (cabin mass 600 kg) is designed for a maximum load of 2100 kg, and to reach a velocity of 3.1 m/s in 3 s. For this scenario, what is the tension the elevator rope has to withstand?

This is what I've tried and is incorrect.

2100kg + 600 kg= 2700kg (m)

(3.1/3)= 1.033m/s^2 (a)

2700 x 1.033= 2789.1N (F)

Please help.

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