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November 26, 2014

November 26, 2014

Posted by **Chrissey** on Tuesday, September 25, 2012 at 10:25am.

- Maths - Arithmetic Progression -
**Steve**, Tuesday, September 25, 2012 at 11:35amT4 = a+3d = 8

S10 = 5(2a+9d) = 40

a = 16

d = -8/3

T1 = 16

T10 = 16 + 9(-8/3) = -8

check, sequence is

16 40/3 32/3 8 16/3 8/3 0 -8/3 -16/3 -8 ...

Sum of 1st 10 terms = 40

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