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July 29, 2014

July 29, 2014

Posted by **Math** on Tuesday, September 25, 2012 at 10:07am.

- Geometric Progression -
**Reiny**, Tuesday, September 25, 2012 at 1:23pm10000 = 2000(1 - 1.1^-n)/.1

5 = (1 - 1.1^-n)/.1

.5 = 1 - 1.1^-n

1.1^-n = .5

log both sides

-n log 1.1 = log .5

-n = log .5/log 1.1 = -7.27

n = 7.27

or appr 7 and 1/4 years

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