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August 30, 2014

August 30, 2014

Posted by **amadorlinas** on Tuesday, September 25, 2012 at 2:01am.

- math 2 trigonometry -
**Steve**, Tuesday, September 25, 2012 at 11:16amif the building's height is h,

the distance to P, call it x,

tan60° = h/x

x = h/√3

from h/3, the angle θ has

tanθ = (h/3)/(h/√3) = 1/√3

θ = 30°

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