posted by sam on .
A person weighing 0.6 kN rides in an elevator that has a downward acceleration of 2.3 m/s^2.
The acceleration of gravity is 9.8 m/s^2.
What is the magnitude of the force of the elevator ﬂoor on the person?
Answer in units of kN
m = 600/g = 61.2 kg
force up on object = F
force down on object = m g = 600 N
net force up = F-600
F = m a
F-600 = 61.2 (-2.3)
F = 600 - 141 = 459 N = .459 kN