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March 29, 2017

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A person weighing 0.6 kN rides in an elevator that has a downward acceleration of 2.3 m/s^2.
The acceleration of gravity is 9.8 m/s^2.
What is the magnitude of the force of the elevator floor on the person?
Answer in units of kN

  • Physics - ,

    m = 600/g = 61.2 kg
    force up on object = F
    force down on object = m g = 600 N

    net force up = F-600

    F = m a
    F-600 = 61.2 (-2.3)
    F = 600 - 141 = 459 N = .459 kN

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