Three line segments have the following measure AB=6, BC=3, and AC=8. What conclusions can you draw about points A,B and C?
and how would i draw this
i need help please!
21
To draw conclusions about points A, B, and C, we can use the Triangle Inequality Theorem. According to this theorem, the sum of the lengths of any two sides of a triangle must be greater than the length of the remaining side.
Let's apply this theorem to the given line segments. We have AB = 6, BC = 3, and AC = 8.
1. Comparing AB and BC: AB + BC = 6 + 3 = 9. Since 9 is greater than 8 (the length of AC), point B can be connected to points A and C to form a triangle.
2. Comparing AB and AC: AB + AC = 6 + 8 = 14. Since 14 is greater than BC (length 3), point A can be connected to points B and C to form a triangle.
3. Comparing BC and AC: BC + AC = 3 + 8 = 11. Since 11 is greater than AB (length 6), point C can be connected to points A and B to form a triangle.
From these comparisons, we can conclude that points A, B, and C can be connected to form a triangle.