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April 19, 2015

April 19, 2015

Posted by **Pcwest** on Monday, September 24, 2012 at 6:32pm.

- trig -
**Henry**, Tuesday, September 25, 2012 at 7:24pmX = -23 Mi.

Y = 14 Mi.

tanA = Y/X = 14/-23 = -0.60870

A = -31.33o,CW = 148.7o,CCW.

D = X/cosA = -23/cos148.7 = 26.9 Mi

Bearing = 148.7 - 90 = 58.7o.

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