trig
posted by Pcwest on .
A boat is 23 mi due west of lighthouse A. Lighthouse B is 14 mi due north of lighthousenA. Find the bearing of lighthouse B from the boat and the distance from lighthousenB tho the boat.

X = 23 Mi.
Y = 14 Mi.
tanA = Y/X = 14/23 = 0.60870
A = 31.33o,CW = 148.7o,CCW.
D = X/cosA = 23/cos148.7 = 26.9 Mi
Bearing = 148.7  90 = 58.7o.