At 298K and 1bar pressure, the density of water is 1.00 g/cm^3 , Cpm = and 75.3 J/Kmol. The change in volume with temperature is given by delta V = ViB(deltaT), where B, the coefficient of thermal expansion, is 2.07 * 10^-4 K^-1.

If the temperature of 350g of water is increased by 27.5K , calculate w.

How do I start this question?

Do you have a typo? Cpm = and 75.3 j/kmol makes no sense.

Calculate w but w isn't anywhere in the problem.

It should be and Cpm = and 75.3 J/Kmol. I know w isn't anywhere in the problem which is why I don't know where to start.

and Cpm and 75.3 still doesn't make sense. So what does w stand for. It might help if we knew what we for looking for.

w = work, it's a physical chem question, here c does not mean concentration, it is the heat capacity of pressure/mole

To start this question, we need to understand what variables and equations are given, and what information is being asked for.

We are given the following information:
1. At 298K and 1bar pressure, the density of water is 1.00 g/cm^3.
2. Cpm (specific heat capacity) is a constant equal to 75.3 J/Kmol.
3. The change in volume with temperature is given by delta V = ViB(deltaT), where B, the coefficient of thermal expansion, is 2.07 * 10^-4 K^-1.
4. The temperature of 350g of water is increased by 27.5K.

We are asked to calculate "w", which is not directly mentioned.

To solve this question, we need to apply the appropriate equations and concepts to determine w. We can break down the problem into smaller steps as follows:

Step 1: Determine the initial volume of water (Vi).
The given density of water (1.00 g/cm^3) can help us find the initial volume (Vi) of water. The relationship between density and volume is given by the formula: mass = density * volume.

Step 2: Determine the change in volume of water (delta V).
The change in volume of water can be calculated using the equation: delta V = ViB(deltaT), where B is the coefficient of thermal expansion and deltaT is the change in temperature.

Step 3: Calculate the work done (w).
The work done can be calculated using the equation: w = -PdeltaV, where P is the pressure.

By following these steps, we can determine the value of w, which is the final result sought in the question.