Calculate the molarity of a 100. mL solution containing 22.3 g of sucrose (C12H22O11)

mols sucrose = grams/molar mass = ?

Then M = mols/L soln
(note: L soln = 0.100)

To calculate the molarity of a solution, you need to know the number of moles of the solute and the volume of the solution in liters.

To determine the number of moles of sucrose (C12H22O11), you will first need to find the molar mass of sucrose.

The molar mass of sucrose can be calculated by adding the individual atomic masses of carbon (C), hydrogen (H), and oxygen (O) in the molecule.

The atomic masses from the periodic table are approximately 12.01 g/mol for carbon, 1.01 g/mol for hydrogen, and 16.00 g/mol for oxygen.

So, the molar mass of C12H22O11 is:

(12.01 g/mol x 12) + (1.01 g/mol x 22) + (16.00 g/mol x 11) = 342.34 g/mol

Now that you know the molar mass of sucrose, you can calculate the number of moles of sucrose using the formula:

moles = mass / molar mass

In this case, the mass of the sucrose is given as 22.3 g, so:

moles = 22.3 g / 342.34 g/mol = 0.0651 mol

Next, you need to convert the volume of the solution from milliliters (mL) to liters (L).

Given that the volume is 100. mL, you divide it by 1000 to obtain 0.100 L.

Finally, you can calculate the molarity using the equation:

Molarity (M) = moles of solute / volume of solution (in liters)

Therefore, the molarity of the solution is:

Molarity = 0.0651 mol / 0.100 L = 0.651 M

So, the molarity of the 100. mL solution containing 22.3 g of sucrose (C12H22O11) is 0.651 M.