Posted by Maria on Monday, September 24, 2012 at 4:57pm.
the initial vertical velocity is __ (2650 m/s) * cos(41.9º)
the time of flight is the initial vertical velocity divided by the gravitational acceleration __ 2 * [(2650 m/s) * sin(41.9º)] / (9.8 m/s^2)
the horizontal velocity is __ (2.65 km/s) * cos(41.9º)
the range is the horizontal velocity multiplied by the flight time
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