Posted by **Booker Perry** on Monday, September 24, 2012 at 4:14pm.

A ball is thrown horizontally from the top of a cliff 50m high with a velocity of 7m/s. How far from the base of the building does the ball land.

This is what I think is how you do the question(Please correct me if I am wrong).

y=vt+.5a(t)²

50=0+.5(9.8)t²

10.204=t²

t=3.194 seconds

x=vt+.5a(t)²

x=(7)(3.194)+.5(0)(3.194)²

x=22.36 m

So is the answer 22.36m?

Please help me if I go wrong

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