Posted by Abraham on Monday, September 24, 2012 at 12:35pm.
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h = 50*sin30° t - 4.9t^2
= 25t - 4.9t^2
= t(25-4.9t)
(a) h=0 at t=0 and t=5.10
(b) max height achieved at t = 25/9.8 = 2.55
h(2.55) = 31.9
(c) x = 5.10 * 50 * cos 30° = 220.8
(d) speeds same as at launch
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