Posted by Amie on Monday, September 24, 2012 at 4:51am.
Second Stone:
d = (V^2-Vo^2)/2g.
d = (158.76-0)/19.6 = 8.1 m.
Tf = (V-Vo)/g = (12.6-0)/9.8 = 1.29 s. =
Fall time.
First Stone:
Tf = 1.51 + 1.29 = 2.80 s.
d = Vo*t + 0.5g*t^2.
d = 0 + 4.9*2.8^2 = 38.3 m.
D = 38.3 - 8.1 = 30.2 Meters apart.
Related Questions
physics - A stone is dropped from the roof of a high building. A second stone is...
Physics - A stone is dropped from rest from the roof of a 100-m high building; 2...
physics - A stone is dropped from a 75 m high building. when this stone has ...
physics - A stone is dropped from a 75 m high building. when this stone has ...
Physics - a stone is dropped from a 75m building. when a stone has dropped 15m, ...
Physics - 1) A car traveling at 22m/s decelerates at a constant 1.5m/s^2. ...
Physics - A stone is dropped from a high altitude and 3 s later another stone is...
physics - A stone is dropped from the roof of a tall building. A person measures...
calculus - use to postion function s(t) = -4.9t^2 + vt + s for free-falling ...
calculus - use to postion function s(t) = -4.9t^2 + vt + s for free-falling ...
For Further Reading
