Posted by Debbie on .
Need to write a brief description of the procedure required to make 900mL of a 0.5 M NaCl solution. The formula weight of NaCl is 58.4g/mole.
How many mols do you want? That M x L = 0.5M x 0.900 L = 0.45 mols NaCl.
Weigh accurately 0.45 mols NaCl (grams = mols x molar mass = 0.45*58.4 = 26.3 g NaCl), completely transfer to a 900 mL volumetric flask, add some water, swirl until all of the NaCl is dissolved, then make to the mark with distilled water.
Note: As far as I know no 900 mL volumetric flasks are manufactured. I would prepare 1000 mL (1 L) of 0.5 M NaCl since 1 L volumetric flasks are available.
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