Posted by Brynn on Sunday, September 23, 2012 at 10:51pm.
Your equation should read
h(t) = -9.8t^2 + 100
when t = 3
h(3) = -9.8(9) + 100
= 11.8
it will be 11.8 m above the ground
how long to hit ground ??
when h(t) = 0
0 = -9.8t^2 + 100
9.8t^2 = 100
t^2 = 100/9.8 = 10.204..
t = √10.204.. = appr 3.2 seconds
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